# exam3physics4am25 .pdf

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### Aperçu du document

‫‪ ‬‬

‫‪20152014–‬‬

‫‪ 4‬‬
‫ﺍﻟﺠﺰﺀ ﺍﻷﻭﻝ ‪ 12 ):‬ﻧﻘﺎﻁ (‬

‫ﺍﻟﺘﻤﺮﻳﻦ ﺍﻷﻭﻝ ‪ 06 ) :‬ﻧﻘﺎﻁ (‬
‫‪ - I‬ﻧﻀﻊ ﻓﻲ ﺇﻧﺎﺀ ﻛﻤﻴﺔ ﻣﻦ ﺍﻟﻤﺎﺀ ﺍﻟﻤﻘﻄﺮ ﻛﻤﺎ ﻫﻮ ﻣﻮﺿﺢ ﻓﻲ ﺍﻟﻮﺛﻴﻘﺔ ‪.‬‬
‫‪0.5‬ﻥ‬

‫ﺑﻄﺎرﻳﺔ‬

‫‪-‬‬

‫‪ (1‬ﻣﺎﺫﺍ ﻳﺤﺪﺙ ﻟﻠﻤﺼﺒﺎﺡ ﻋﻨﺪ ﻏﻠﻖ ﺍﻟﻘﺎﻃﻌﺔ ؟‬
‫‪ (2‬ﻧﻀﻴﻒ ﻟﻠﻤﺎﺀ ﺍﻟﻤﻘﻄﺮ ﻣﺴﺤﻮﻕ ﻛﻠﻮﺭ ﺍﻟﺮﺻﺎﺹ ‪.‬‬

‫‪01‬ﻥ‬

‫** ﻣﺎﺫﺍﻳﺤﺪﺙ ﻟﻠﻤﺼﺒﺎﺡ ﻋﻨﺪ ﻏﻠﻖ ﺍﻟﻘﺎﻃﻌﺔ ﻭ ﻟﻤﺎﺫﺍ ؟‬

‫ﻣﺴﺮﻳﺎﻥ ﻣﻦ ﺍﻟﻔﺤﻢ‬

‫‪ -II‬ﻧﺘﺞ ﻋﻦ ﺍﻟﺘﺤﻠﻴﻞ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ﻟﻠﻤﺤﻠﻮﻝ ﺍﻟﺴﺎﺑﻖ )ﻣﺤﻠﻮﻝ ﻛﻠﻮﺭ ﺍﻟﺮﺻﺎﺹ (‬
‫ﺍﻟﺬﻱ ﺻﻴﻐﺘﻪ ﺍﻟﻜﻴﻤﻴﺎﺋﻴﺔ ‪ ،PbCl2‬ﺍﻧﻄﻼﻕ ﻏﺎﺯ ﻋﻨﺪ ﺍﻟﻤﺼﻌﺪ ﻭ ﺗﺮﺳﺐ ﻣﻌﺪﻥ ﻋﻨﺪ ﺍﻟﻤﻬﺒﻂ‪.‬‬
‫‪0.5‬ﻥ‬

‫‪ (1‬ﺍﻛﺘﺐ ﺍﻟﺼﻴﻐﺔ ﺍﻟﻜﻴﻤﻴﺎﺋﻴﺔ ﺍﻟﺸﺎﺭﺩﻳﺔ ﻟﻤﺤﻠﻮﻝ ﻛﻠﻮﺭ ﺍﻟﺮﺻﺎﺹ ‪.‬‬

‫‪02‬ﻥ‬

‫‪ (2‬ﻧﻤﺬﺝ ﺍﻟﺘﻔﺎﻋﻞ ﺍﻟﻜﻴﻤﻴﺎﺋﻲ ﺑﻤﻌﺎﺩﻟﺔ ﻛﻴﻤﻴﺎﺋﻴﺔ ﻋﻨﺪ ﻛﻞ ﻣﻦ ‪ :‬ﺍﻟﻤﻬﺒﻂ ﻭ ﺍﻟﻤﺼﻌﺪ ‪.‬‬
‫‪-‬‬

‫‪-III‬ﻧﻀﻴﻒ ﻟﻠﻤﺤﻠﻮﻝ ﺍﻟﺴﺎﺑﻖ )ﻣﺤﻠﻮﻝ ﻛﻠﻮﺭ ﺍﻟﺮﺻﺎﺹ( ﻛﻤﻴﺔ ﻣﻦ ﻣﺤﻠﻮﻝ ﻧﺘﺮﺍﺕ ﺍﻟﻔﻀﺔ ) ‪(Ag +NO3‬‬
‫‪+‬‬

‫ﻓﻴﻨﺘﺞ ﺟﺴﻤﺎﻥ ﺃﺣﺪﻫﻤﺎ ﻋﻠﻰ ﺷﻜﻞ ﺭﺍﺳﺐ ﺃﺑﻴﺾ ﻳﺴﻮﺩ ﻋﻨﺪ ﻭﺟﻮﺩ ﺍﻟﻀﻮﺀ‪.‬‬
‫‪0.5‬ﻥ‬
‫‪1.5‬ﻥ‬

‫‪ (1‬ﻣﺎ ﻫﻲ ﺍﻟﺸﺎﺭﺩﺓ ﺍﻟﻤﺮﺍﺩ ﺍﻟﻜﺸﻒ ﻋﻨﻬﺎ ؟‬
‫‪(2‬ﺃﻛﺘﺐ ﻣﻌﺎﺩﻟﺔ ﺍﻟﺘﻔﺎﻋﻞ ﺍﻟﻜﻴﻤﻴﺎﺋﻲ ﺍﻟﺤﺎﺩﺙ ﺑﻴﻦ ﻫﺬﻳﻦ ﺍﻟﻤﺤﻠﻮﻟﻴﻦ ﺑﺎﻟﺼﻴﻐﺔ ﺍﻟﺸﺎﺭﺩﻳﺔ‪.‬‬

‫ﺍﻟﺘﻤﺮﻳﻦ ﺍﻟﺜﺎﻧﻲ‪ 06) :‬ﻧﻘﺎﻁ(‬
‫ﻭﻗﻒ ﺃﺣﻤﺪ ﺃﻣﺎﻡ ﻣﺮﺁﺓ ﻣﺴﺘﻮﻳﺔ ﻋﻠﻰ ﺑﻌﺪ ‪. 60Cm‬‬
‫‪02‬ﻥ‬

‫‪ (1‬ﻛﻢ ﻳﺴﺎﻭﻱ ﺍﻟﺒﻌﺪ ﺑﻴﻨﻪ ﻭ ﺑﻴﻦ ﺻﻮﺭﺗﻪ ؟ ﻣﻊ ﺍﻟﺘﺒﺮﻳﺮ ‪.‬‬
‫‪ (2‬ﺳﻠﻂ ﺃﺣﻤﺪ ﺷﻌﺎﻋﺎ ﺿﻮﺋﻴﺎ ﻋﻠﻰ ﺍﻟﻤﺮﺁﺓ ﺍﻟﺴﺎﺑﻘﺔ ) ﺃﻧﻈﺮ ﺍﻟﺸﻜﻞ (‬

‫‪01‬ﻥ‬

‫ﺃ‪ /‬ﻛﻢ ﺗﺴﺎﻭﻱ ﺯﺍﻭﻳﺔ ﺍﻟﻮﺭﻭﺩ ؟‬

‫‪02‬ﻥ‬

‫ﺏ‪ /‬ﻛﻢ ﺗﺴﺎﻭﻱ ﺯﺍﻭﻳﺔ ﺍﻻﻧﻌﻜﺎﺱ ﻣﻊ ﺍﻟﺘﺒﺮﻳﺮ؟‬

‫‪N‬‬
‫‪s‬‬

‫‪ (3‬ﻧﺪﻳﺮ ﺍﻟﻤﺮﺁﺓ ‪ M‬ﺑﺰﺍﻭﻳﺔ ‪ 10‬ﻓﻲ ﺟﻬﺔ ﺩﻭﺭﺍﻥ ﻋﻘﺎﺭﺏ ﺍﻟﺴﺎﻋﺔ ‪.‬‬
‫‪0‬‬

‫‪01‬ﻥ‬

‫‪300‬‬

‫** ﻣﺎ ﻫﻲ ﻗﻴﻤﺔ ﺍﻟﺰﺍﻭﻳﺔ ﺍﻟﺘﻲ ﻳﺪﻭﺭ ﺑﻬﺎ ﺍﻟﺸﻌﺎﻉ ﺍﻟﻤﻨﻌﻜﺲ ؟‬

‫‪M‬‬
‫‪o‬‬

‫ﺍﻟﺼﻔﺤﺔ‪2/1‬‬

‫ﺃﻗﻠﺐ ﺍﻟﺼﻔﺤﺔ‬

‫ﺍﻟﺠﺰﺀ ﺍﻟﺜﺎﻧﻲ ‪ 08 ):‬ﻧﻘﺎﻁ (‬

‫ﺍﻟﻮﺿﻌﻴﺔ ﺍﻻﺩﻣﺎﺟﻴﺔ ‪:‬‬

‫ﺃﺛﻨﺎﺀ ﺣﻀﻮﺭﻙ ﻟﺤﻔﻞ ﺃﻗﺎﻣﺘﻪ ﺍﺳﺮﺓ ﺻﺪﻳﻘﻚ ﻟﻴﻼ ‪ .‬ﻭﻋﻨﺪ ﺗﺸﻐﻴﻞ ﻓﺮﻥ ﻛﻬﺮﺑﺎﺋﻲ ﺍﻧﻘﻄﻊ ﺍﻟﺘﻴﺎﺭ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ‬
‫ﻋﻦ ﺍﻟﻤﻨﺰﻝ ﺑﻮﺍﺳﻄﺔ ﺍﻟﻘﺎﻃﻊ ﺍﻵﻟﻲ ﺗﻠﻘﺎﺋﻴﺎ ‪.‬ﺣﺎﻭﻝ ﺻﺪﻳﻘﻚ ﻣﺤﻤﺪ ﺍﺳﺘﺮﺟﺎﻉ ﺍﻟﺘﻴﺎﺭ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ﺑﺎﺳﺘﻌﻤﺎﻝ‬
‫ﻧﻔﺲ ﺍﻟﻘﺎﻃﻊ ﻟﻜﻦ ﺩﻭﻥ ﺟﺪﻭﻯ‪.‬ﻓﻌﻠﻖ ﻗﺎﺋﻼ ﻟﻮ ﻛﺎﻥ ﺑﺎﻟﻤﻨﺰﻝ ﻣﺄﺧﺬ ﺃﺭﺿﻲ ﻟﻤﺎ ﺍﻧﻘﻄﻊ ﺍﻟﺘﻴﺎﺭ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ﻋﻦ‬
‫ﺍﻟﻤﻨﺰﻝ ‪.‬‬
‫‪ (1‬ﻣﺎ ﺭﺃﻳﻚ ﻓﻲ ﻗﻮﻝ ﻣﺤﻤﺪ ؟‬
‫‪ -(2‬ﻓﺴﺮ ﻟﺼﺪﻳﻘﻚ ﻣﺤﻤﺪ ﺳﺒﺐ ﺍﻧﻘﻄﺎﻉ ﺍﻟﺘﻴﺎﺭ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ﻋﻦ ﺍﻟﻤﻨﺰﻝ ؟‬
‫‪ -(3‬ﺍﻗﺘﺮﺡ ﻋﻠﻰ ﻣﺤﻤﺪ ﺣﻼ ﻳﺴﻤﺢ ﺑﺈﺿﺎﻓﺔ ﺗﺸﻐﻴﻞ ﺍﻟﻔﺮﻥ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ﺩﻭﻥ ﺍﻧﻘﻄﺎﻉ ﺍﻟﺘﻴﺎﺭ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ؟‬
‫‪ -(4‬ﺍﻋﺪ ﺭﺳﻢ ﺍﻟﻤﺨﻄﻂ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ﻳﺴﻤﺢ ﺑﺘﺸﻐﻴﻞ ﺍﻟﻔﺮﻥ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ﻣﺒﻴﻨﺎ ﻋﻠﻴﻪ ﺍﻟﺘﻌﺪﻳﻼﺕ‬
‫ﻭ ﺍﻹﺿﺎﻓﺎﺕ ﻟﺤﻤﺎﻳﺔ ﺍﻷﺟﻬﺰﺓ ﺍﻟﻜﻬﺮﺑﺎﺋﻴﺔ ﻭ ﻣﺴﺘﻌﻤﻠﻴﻬﺎ ﻣﻦ ﺃﺧﻄﺎﺭ ﺍﻟﺘﻴﺎﺭ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ‪.‬‬

‫‪P‬‬
‫‪N‬‬

‫اﻧﺘﮭــــــــــــﻰ‬

‫اﻟﺼﻔﺤﺔ ‪2 / 2‬‬

‫ﺑﺎﻟﺘﻮﻓﯿـــــــﻖ‬

‫ﺍﻻﺟﺎﺑﺔ ﺍﻟﻨﻤﻮﺫﺟﻴﺔ‬

‫ﺍﻟﺠﺰﺀ ﺍﻷﻭﻝ ‪ 12 ):‬ﻧﻘﺎﻁ (‬

‫ﺍﻟﺘﻤﺮﻳﻦ ﺍﻷﻭﻝ ‪ 06 ) :‬ﻧﻘﺎﻁ (‬

‫‪-I‬‬
‫‪ (1‬ﻧﻼﺣﻆ ﻋﻨﺪ ﻏﻠﻖ ﺍﻟﻘﺎﻃﻌﺔ‪ :‬ﻻ ﻳﺤﺪﺙ ﺷﺊ‬

‫‪0.5‬ﻥ‬

‫ﻧﻀﻴﻒ ﻟﻠﻤﺎﺀ ﺍﻟﻤﻘﻄﺮ ﻣﺴﺤﻮﻕ ﻛﻠﻮﺭ ﺍﻟﺮﺻﺎﺹ ‪.‬‬
‫‪ (2‬ﻋﻨﺪ ﻏﻠﻖ ﺍﻟﻘﺎﻃﻌﺔ ﻧﻼﺣﻆ‪ :‬ﺗﻮﻫﺞ ﺍﻟﻤﺼﺒﺎﺡ‬

‫‪0.5‬ﻥ‬

‫ﻷﻧﻪ ﻣﺤﻠﻮﻝ ﺷﺎﺭﺩﻱ ﻧﺎﻗﻞ ﻟﻠﺘﻴﺎﺭ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ ‪0.5‬ﻥ‬
‫‪-II‬‬
‫‪ (1‬ﺍﻟﺼﻴﻐﺔ ﺍﻟﻜﻴﻤﻴﺎﺋﻴﺔ ﺍﻟﺸﺎﺭﺩﻳﺔ ﻟﻤﺤﻠﻮﻝ ﻛﻠﻮﺭ ﺍﻟﺮﺻﺎﺹ ‪0.5 (Pb + 2Cl ) :‬ﻥ‬
‫‪-‬‬

‫‪2+‬‬

‫‪ (2‬ﻧﻤﺬﺟﺔ ﺍﻟﺘﻔﺎﻋﻞ ﺍﻟﻜﻴﻤﻴﺎﺋﻲ ﺑﻤﻌﺎﺩﻟﺔ ﻛﻴﻤﻴﺎﺋﻴﺔ ‪:‬‬
‫‪Pb2++2é‬‬
‫‪Pb‬‬
‫‪1‬ﻥ‬
‫ﻋﻨﺪ ﺍﻟﻤﻬﺒﻂ‪.‬‬
‫ﻋﻨﺪ ﺍﻟﻤﺼﻌﺪ ‪.‬‬
‫‪-III‬‬

‫‪Cl2 + 2é‬‬
‫‪2‬‬

‫‪1‬ﻥ‬

‫‪2Cl-‬‬

‫‪ (1‬ﻳﺪﻝ ﻇﻬﻮﺭ ﺭﺍﺳﺐ ﺃﺑﻴﺾ ﻳﺴﻮﺩ ﻋﻨﺪ ﻭﺟﻮﺩ ﺍﻟﻀﻮﺀ ‪ :‬ﻋﻠﻰ ﻭﺟﻮﺩ ﺷﺎﺭﺩﺓ ﺍﻟﻜﻠﻮﺭ ‪0.5 Cl‬ﻥ‬
‫‪-‬‬

‫‪ (2‬ﻣﻌﺎﺩﻟﺔ ﺍﻟﺘﻔﺎﻋﻞ ﺑﻴﻦ ﺍﻟﻤﺤﻠﻮﻟﻴﻦ ﺑﺎﻟﺼﻴﻐﺔ ﺍﻟﺸﺎﺭﺩﻳﺔ‪.‬‬
‫) ‪(Pb2+ + 2NO3 ) +2 (Ag + Cl-‬‬
‫‪-‬‬

‫‪+‬‬

‫) ‪1.5 (Pb2++ 2Cl-)+ 2 (Ag + NO3‬ﻥ‬
‫‪-‬‬

‫‪+‬‬

‫ﺍﻟﺘﻤﺮﻳﻦ ﺍﻟﺜﺎﻧﻲ‪ 06) :‬ﻧﻘﺎﻁ(‬
‫‪ (1‬ﻳﺴﺎﻭﻱ ﺍﻟﺒﻌﺪ ﺑﻴﻨﻪ ﻭ ﺑﻴﻦ ﺻﻮﺭﺗﻪ ‪01 ....... 120Cm‬ﻥ‬
‫ﺍﻟﺘﺒﺮﻳﺮ ‪:‬ﻷﻥ ﻣﻦ ﺧﺼﺎﺋﺺ ﺍﻟﺼﻮﺭﺓ ﺍﻻﻓﺘﺮﺍﺿﻴﺔ ﺃﻧﻬﺎ ﻣﻨﺎﻇﺮﺓ ﻟﻠﺠﺴﻢ ﺑﺎﻟﻨﺴﺒﺔ ﻟﻠﻤﺮﺁﺓ ‪01 ....‬ﻥ‬
‫‪(2‬‬
‫ﺃ‪ /‬ﺗﺴﺎﻭﻱ ﺯﺍﻭﻳﺔ ﺍﻟﻮﺭﻭﺩ ‪01 ....................... i =60‬ﻥ‬
‫‪0‬‬

‫ﺏ‪ /‬ﺗﺴﺎﻭﻱ ﺯﺍﻭﻳﺔ ﺍﻻﻧﻌﻜﺎﺱ‬

‫‪01 ............ r =600‬ﻥ‬

‫ﺍﻟﺘﺒﺮﻳﺮ‪ :‬ﻷﻥ ﺯﺍﻭﻳﺔ ﺍﻟﻮﺭﻭﺩ = ﺯﺍﻭﻳﺔ ﺍﻻﻧﻌﻜﺎﺱ‪01 ........‬ﻥ‬
‫‪(3‬‬
‫** ﻗﻴﻤﺔ ﺍﻟﺰﺍﻭﻳﺔ ﺍﻟﺘﻲ ﻳﺪﻭﺭ ﺑﻬﺎ ﺍﻟﺸﻌﺎﻉ ﺍﻟﻤﻨﻌﻜﺲ ‪.‬‬

‫ﻋﻠﻤﺎ أن‬
‫و ﻣﻨﮫ‬

‫‪ 0.5‬ن‬
‫‪10×2‬‬
‫‪200‬‬

‫‪0.5......‬‬

‫ﺍﻟﺠﺰﺀ ﺍﻟﺜﺎﻧﻲ ‪ 08 ):‬ﻧﻘﺎﻁ (‬

‫ﺍﻟﻮﺿﻌﻴﺔ ﺍﻻﺩﻣﺎﺟﻴﺔ ‪:‬‬

‫‪ (1‬ﻗﻮﻝ ﻣﺤﻤﺪ ‪ :‬ﺧﻄﺄ‬
‫‪ -(2‬ﺍﻟﺴﺒﺐ‬
‫)ﺃﻱ ﺯﻳﺎﺩﺓ ﻓﻲ ﺍﻟﺤﻤﻮﻟﺔ ( ﺃﻱ ﺷﺪﺓ ﺍﻟﺘﻴﺎﺭ ﺍﻟﻤﺎﺭﺓ ﻓﻲ ﺍﻟﺪﺍﺭﺓ ﻋﻨﺪ ﺗﺸﻐﻴﻠﻬﺎ ﺍﻛﺒﺮ ﻣﻦ ﺷﺪﺓ ﺍﻟﺘﻴﺎﺭ‬
‫ﺍﻟﺘﻲ ﻳﺴﻤﺢ ﺑﻬﺎ ﺍﻟﻘﺎﻃﻊ ﺍﻟﺘﻔﺎﺿﻠﻲ‬
‫‪ -(3‬ﺍﻟﺤﻞ ﺍﻟﻤﻘﺘﺮﺡ ‪:‬‬
‫ﺯﻳﺎﺩﺓ ﻓﻲ ﻗﻴﻤﺔ ﺷﺪﺓ ﺍﻟﺘﻴﺎﺭ )ﺍﺳﺘﺒﺪﺍﻝ ﺍﻟﻘﺎﻃﻊ ﺍﻟﺘﻔﺎﺿﻠﻲ ﻳﺘﺤﻤﻞ ﺷﺪﺓ ﺗﻴﺎﺭ ﺍﻛﺒﺮ‬

‫(‬

‫‪ -(4‬ﺭﺳﻢ ﺍﻟﻤﺨﻄﻂ ﺍﻟﻜﻬﺮﺑﺎﺋﻲ‬
‫‪P‬‬
‫‪N‬‬

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