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ﺣﻞ ﺳﻠﺴﻠﺔ اﻟﺘﻤﺎرﻳﻦ رﻗﻢ 1
اﻟﺘﻤﺮﻳﻦ اﻷول :
1
Chaine de caractères
""faux
""al4
""maison
""125
Booléen
vrai
Réel
7.25
-18.45
433.0
Entier
817
-315
2
اﻟﺘﻌﻠﻴﻞ
اﻹﺟﺎﺑﺔ ) ﺻﺤﻴﺢ أم ﺧﻄﺄ ؟(
ﻳﺤﺘﻮي ﻋﻠﻰ رﻣﺰﻳﻦ
ﻳﺤﺘﻮي ﻋﻠﻰ رﻣﺰﻳﻦ
ﻳﺤﺘﻮي ﻋﻠﻰ رﻣﺰ
ﻳﺤﺘﻮي ﻋﻠﻰ رﻣﺰ
ﻳﺤﺘﻮي ﻋﻠﻰ رﻣﺰﻳﻦ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
ﺻﺤﻴﺢ
ﺻﺤﻴﺢ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
)Mot clé (instruction
ﻳﺒﺪأ ﺑﺮﻗﻢ
ﻳﻄﺒﻖ آﻞ اﻟﺸﺮوط
ﻳﻄﺒﻖ آﻞ اﻟﺸﺮوط
ﻳﺤﺘﻮي ﻋﻠﻰ رﻣﺰ
ﻳﺒﺪأ ﺑﺮﻗﻢ
ﻳﺤﺘﻮي ﻋﻠﻰ رﻣﺰ
Mot clé
أﺳﻤﺎء اﻟﻤﺘﻐﻴﺮات
""z
""2
3%
*
’’X
lire
2a
bb
c2
π
6s
’X
Début
اﻟﺘﻤﺮﻳﻦ اﻟﺜﺎﻧﻲ :
أو :
C Å x^2 + 2*x – 9
2ab
c+1
4
1A = 9xy
AÅ9*x*y
2B = 9x – 1
)D Å2*a*b/(c+1
BÅ9*x–1
5X = ((a+b)c)d
3C = x2 +2x – 9
X Å (a+b)**c**d
C Å x**2 + 2*x – 9
(a + b)2
)W Å (a+b)/(1/(c-d)**2
3
)9T = ((a-b)c
Y Å (a+b)**2/(c-d)**3
T Å (a-b)**c
= 7Z
))Z Å SQRT (a+b-(c+d
5αβ
5
β
3
α
c-d
6
= 8W
2
))F Å (5*x+1)**2+5*al*be/(2+SQRT(al+5/3*be
اﻟﺘﻤﺮﻳﻦ اﻟﺜﺎﻟﺚ :
1X = 7-42+32+13-10/2+23
)اﻷوﻟﻮﻳﺔ ﻟﻸس ﻣﻦ اﻟﻴﺴﺎر إﻟﻰ اﻟﻴﻤﻴﻦ(
X Å 7-4**2+3**2+13-10/2+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻠﻘﺴﻤﺔ(
)اﻷوﻟﻮﻳﺔ ﻟﻠﺠﻤﻊ و اﻟﻄﺮح ﻣﻦ اﻟﻴﺴﺎر إﻟﻰ اﻟﻴﻤﻴﻦ(
X Å 7-16+9+13-10/2+8
X Å 7-16+9+13-5+8
X Å 16
)2Y = 7-(42+32)2+13-10/(2+23
)اﻷوﻟﻮﻳﺔ ﻟﻸﻗﻮاس ﻋﻠﻰ اﻟﻴﺴﺎر ،داﺧﻞ اﻷﻗﻮاس اﻷوﻟﻮﻳﺔ ﻟﻸس( )Y Å 7-(4**2+3)**2+13-10/(2+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻸﻗﻮاس ﻋﻠﻰ اﻟﻴﺴﺎر(
)Y Å 7- (16+3)**2+13-10/(2+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻸﻗﻮاس ،داﺧﻞ اﻷﻗﻮاس اﻷوﻟﻮﻳﺔ ﻟﻸس( )Y Å 7-19**2+13-10/(2+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻸﻗﻮاس(
)Y Å 7-19**2+13-10/(2+8
)اﻷوﻟﻮﻳﺔ ﻟﻸس(
Y Å 7-19**2+13-10/10
)اﻷوﻟﻮﻳﺔ ﻟﻠﻘﺴﻤﺔ(
Y Å 7-361+13-10/10
)اﻷوﻟﻮﻳﺔ ﻟﻠﺠﻤﻊ و اﻟﻄﺮح ﻣﻦ اﻟﻴﺴﺎر إﻟﻰ اﻟﻴﻤﻴﻦ( Y Å 7-361+13-1
Y Å-342
3Z = 7-42+(32+13)-(10/2)+23
)اﻷوﻟﻮﻳﺔ ﻟﻸﻗﻮاس ﻋﻠﻰ اﻟﻴﺴﺎر ،داﺧﻞ اﻷﻗﻮاس اﻷوﻟﻮﻳﺔ ﻟﻸس(Z Å 7-4**2+(3**2+13)-(10/2)+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻸﻗﻮاس ﻋﻠﻰ اﻟﻴﺴﺎر( Z Å 7-4**2+(9+13)-(10/2)+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻸﻗﻮاس( Z Å 7-4**2+22-(10/2)+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻸس ﻋﻠﻰ اﻟﻴﺴﺎر(
)اﻷوﻟﻮﻳﺔ ﻟﻸس(
Z Å 7-4**2+22-5+2**3
Z Å 7-16+22-5+2**3
)اﻷوﻟﻮﻳﺔ ﻟﻠﺠﻤﻊ و اﻟﻄﺮح ﻣﻦ اﻟﻴﺴﺎر إﻟﻰ اﻟﻴﻤﻴﻦ(
Z Å 7-16+22-5+8
Z Å 16
اﻟﺘﻤﺮﻳﻦ اﻟﺮاﺑﻊ :
√
√
1
)اﻟﺼﻴﻐﺔ اﻟﻤﻌﻠﻮﻣﺎﺗﻴﺔ(
)X Å SQRT(a+b)/SQRT(a+20
)اﻟﺘﻌﻮﻳﺾ(
)X Å SQRT(5+4)/SQRT(5+20
)اﻟﺤﺴﺎب ﺣﺴﺐ اﻷوﻟﻮﻳﺎت(
)X Å SQRT(9)/SQRT(25
X Å 3/5
X Å 0.6
2
)اﻟﺼﻴﻐﺔ اﻟﻤﻌﻠﻮﻣﺎﺗﻴﺔ(
)اﻟﺘﻌﻮﻳﺾ(
))Y Å (a/b-c/d)/(1/(a*b**2
))Y Å (5/4-10/2)/(1/(5*4**2
)اﻟﺤﺴﺎب ﺣﺴﺐ اﻷوﻟﻮﻳﺎت(
))Y Å (1.25-5)/(1/(5*4**2
))Y Å 3.75/(1/(5*4**2
))Y Å 3.75/(1/(5*16
)Y Å 3.75/(1/80
Y Å 3.75/0.0125
Y Å -300
3
|
|
A Å y**(4*x)/(y**z-t**w)-ABS(x-z)
()اﻟﺼﻴﻐﺔ اﻟﻤﻌﻠﻮﻣﺎﺗﻴﺔ
A Å 6**(4*(1/2))/(6**2-3**4)-ABS(1/2-2)
()اﻟﺘﻌﻮﻳﺾ
A Å 6**(4*0.5)/(6**2-3**4)-ABS(1/2-2)
()اﻟﺤﺴﺎب ﺣﺴﺐ اﻷوﻟﻮﻳﺎت
A Å 6**2/(6**2-3**4)-ABS(1/2-2)
A Å 6**2/(36-81)-ABS(1/2-2)
A Å 6**2/(-45)-ABS(-1.5)
A Å 6**2/(-45)-1.5
A Å 36/(-45)-1.5
A Å -0.8-1.5
A Å -2.3
: اﻟﺘﻤﺮﻳﻦ اﻟﺨﺎﻣﺲ
اﻟﺘﺼﺮﻳﺢ
a,a1 : entier
b : réel
c : booléen
d : caractère
e : chaîne de caractères
اﻟﺘﺨﺼﻴﺺ
eÅd
cÅd
dÅe
aÅb
a Å a+2
dÅc
bÅa
a Å a1
cÅb
fÅa
(اﻹﺟﺎﺑﺔ ) ﺻﺤﻴﺢ أم ﺧﻄﺄ ؟
ﺻﺤﻴﺢ
ﺧﻄﺄ
ﺧﻄﺄ
ﺧﻄﺄ
ﺻﺤﻴﺢ
ﺧﻄﺄ
ﺻﺤﻴﺢ
ﺻﺤﻴﺢ
ﺧﻄﺄ
ﺧﻄﺄ
: اﻟﺘﻤﺮﻳﻦ اﻟﺴﺎدس
اﻟﻌﺒﺎرة
اﻟﻨﺘﻴﺠﺔ
ﻧﻮع اﻟﻨﺘﻴﺠﺔ
A Å 16
A prend la valeur 16
B Å 40
B prend la valeur 40
N Å 16+40
N Å 56
N prend la valeur 56
P Å 16/25
P Å 0.64
P prend la valeur 0.64
R Å 40/4
R Å 10.0
R prend la valeur 10.0
C prend la valeur "Université"
D prend la valeur " Alger3"
E Å "Université" + " Alger3"
E Å "Université Alger3"
E prend la valeur "Université Alger3"
H Å vrai
H prend la valeur vrai
G Å faux
G prend la valeur faux
F Å vrai
F prend la valeur vrai
K Å vrai et faux ou vrai
K Å faux ou vrai
K Åvrai
K prend la valeur vrai
J Å faux et vrai et vrai
J Å faux et vrai
J Åfaux
J prend la valeur faux
Entier
B Å 8*5
N Å A+B
P Å A/25
R Å B/4
C Å "Université"
D Å " Alger3"
E Å C+D
H Å 1<8
G Å 2>4
F Å 3<5
K Å F et G ou H
J Å G et F et H
Entier
Entier
Réel
Réel
Chaîne de caractères
Chaîne de caractères
Chaîne de caractères
Booléen
Booléen
Booléen
Booléen
Booléen




